摘要
以二氧化锰为微波吸收剂,采用微波辐射法成功合成了CaMoO4∶Eu3+红色发光材料。用X射线粉末衍射仪、扫描电子显微镜、荧光分光光度计分别对样品的物相结构、形貌和发光性质进行了分析和表征。结果表明:所合成的CaMoO4∶Eu3+晶体结构与CaMoO4相似,属四方晶系结构;样品大颗粒呈立方形,尺寸约4～8μm,是由200～300nm的类球形颗粒组装而成。样品的激发光谱由位于200～350 nm的一个宽带和350～500 nm的一系列尖峰组成,最大激发峰位于305 nm处;发射光谱由位于550～750 nm的一系列尖峰组成,最强的发射峰位于617 nm处,归属于Eu3+的5D0→7F2跃迁。当反应时间为40 min,微波功率为中高火,电荷补偿剂Li+的掺杂量为8mol%时,样品的发光强度最大,约为未掺杂电荷补偿剂样品的4倍。
Red phosphors CaMoO4：Eu3＋ were synthesized rapidly by microwave radiation method using MnO2 as absorber.The phase structure,morphology and luminescent properties of the as-synthesized phosphors were investigated by X-ray powder diffraction,Scanning electron microscope and Fluorescence spectrophotometer.The results show that as-synthesized CaMoO4：Eu3＋ phosphors possess the similar tetragonal crystal structure as that of CaMoO4.The big particles of CaMoO4：Eu3＋ are cubic in shape with the edge size about 4-8 μm,which is assembled by spherical particles with a diameter of 200-300 nm.The excitation spectrum of CaMoO4：Eu3＋ is composed by a broad band ranging from 200 nm to 350 nm and a series of peaks from 350 nm to 500 nm.The main peak is at 305 nm.The emission spectrum is composed of a series of peaks from 550 nm to 750 nm and the main peak is at 617 nm due to the 5D0→7F2 transition of Eu3＋.When the reaction time is 40 min,microwave power is middle-high fire and the doping amount of charge compensation agent Li＋ is 8mol%,the sample has the strongest luminous intensity.It is about 4 times of the sample with no doping compensation agent.
出处
《人工晶体学报》
EI
CAS
CSCD
北大核心
2012年第5期1216-1220,共5页
Journal of Synthetic Crystals
基金
国家自然科学基金(20675023)资助项目
